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0.212x^2+9.9x-189.675=0
a = 0.212; b = 9.9; c = -189.675;
Δ = b2-4ac
Δ = 9.92-4·0.212·(-189.675)
Δ = 258.8544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.9)-\sqrt{258.8544}}{2*0.212}=\frac{-9.9-\sqrt{258.8544}}{0.424} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.9)+\sqrt{258.8544}}{2*0.212}=\frac{-9.9+\sqrt{258.8544}}{0.424} $
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